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正则表达式,生成器,迭代器

2022-07-17 05:22:00 我是渣渣辉


1.定义一个生成器函数

生成1-10
使用next(generator)方法获取1-10
使用for循环获取

def generator():
    for i in range(1, 11):
        yield i


gen = generator()
print(next(gen))
print(next(gen))
print(next(gen))
print(next(gen))
print(next(gen))
print(next(gen))
print(next(gen))
print(next(gen))
print(next(gen))
print(next(gen))

2.模拟range的功能,自己建立一个range:MyRange

range(10)
range(1, 10)
range(1, 10, 1) =>
start, stop, step
range(10, 1, -1)
range(10, -1, -1)
range(-10, -1, 1)
range(-1, -10, -1)

class MyRange:
    def __init__(self, start, stop, step=0):
        self.start = start
        self.stop = stop
        self.step = step

    def __iter__(self):
        return self

    def __next__(self):
        if self.step == 0:
            self.step = 1
        if self.step > 0:
            if self.start < self.stop:
                se = self.start
                self.start += self.step
                return se
            else:
                raise StopIteration
        else:
            if self.start > self.stop:
                se = self.start
                self.start += self.step
                return se
            else:
                raise StopIteration


print(list(MyRange(10, 1, -1)))
print(list(MyRange(10, -1, -1)))
print(list(MyRange(-10, -1, 1)))
print(list(MyRange(-1, -10, -1)))

3. re中函数的使用(自己写用例来使用):

""" match fullmatch search findall finditer split sub subn complie """
print(re.match('pattern', 'pattern asdf'))
print(re.match('pattern', 'paasdern asdf'))
print(re.fullmatch("pattern", 'pattern'))
print(re.fullmatch("pattern", 'pattern asdf'))
print(re.search("pattern", "asdpatternads"))
print(re.search("pattern", "asdpaternads"))
print(re.findall('pattern', "pattern pattern asdpattern"))
iter_or = re.finditer("pattern", "pattern pattern asdpattern")
for i in iter_or:
    print(i)
print(re.split(r'\.', 'asd.txt'))
print(re.sub('pattern', '.', "pattern pattern asdpattern"))
print(re.subn('pattern', '.', "pattern pattern asdpattern"))
print(re.compile('asd'))
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本文为[我是渣渣辉]所创,转载请带上原文链接,感谢
https://blog.csdn.net/m0_63342921/article/details/125700458